Convert 53 from decimal to binary
(base 2) notation:
Power Test
Raise our base of 2 to a power
Start at 0 and increasing by 1 until it is >= 53
20 = 1
21 = 2
22 = 4
23 = 8
24 = 16
25 = 32
26 = 64 <--- Stop: This is greater than 53
Since 64 is greater than 53, we use 1 power less as our starting point which equals 5
Build binary notation
Work backwards from a power of 5
We start with a total sum of 0:
25 = 32
The highest coefficient less than 1 we can multiply this by to stay under 53 is 1
Multiplying this coefficient by our original value, we get: 1 * 32 = 32
Add our new value to our running total, we get:
0 + 32 = 32
This is <= 53, so we assign our outside coefficient of 1 for this digit.
Our new sum becomes 32
Our binary notation is now equal to 1
24 = 16
The highest coefficient less than 1 we can multiply this by to stay under 53 is 1
Multiplying this coefficient by our original value, we get: 1 * 16 = 16
Add our new value to our running total, we get:
32 + 16 = 48
This is <= 53, so we assign our outside coefficient of 1 for this digit.
Our new sum becomes 48
Our binary notation is now equal to 11
23 = 8
The highest coefficient less than 1 we can multiply this by to stay under 53 is 1
Multiplying this coefficient by our original value, we get: 1 * 8 = 8
Add our new value to our running total, we get:
48 + 8 = 56
This is > 53, so we assign a 0 for this digit.
Our total sum remains the same at 48
Our binary notation is now equal to 110
22 = 4
The highest coefficient less than 1 we can multiply this by to stay under 53 is 1
Multiplying this coefficient by our original value, we get: 1 * 4 = 4
Add our new value to our running total, we get:
48 + 4 = 52
This is <= 53, so we assign our outside coefficient of 1 for this digit.
Our new sum becomes 52
Our binary notation is now equal to 1101
21 = 2
The highest coefficient less than 1 we can multiply this by to stay under 53 is 1
Multiplying this coefficient by our original value, we get: 1 * 2 = 2
Add our new value to our running total, we get:
52 + 2 = 54
This is > 53, so we assign a 0 for this digit.
Our total sum remains the same at 52
Our binary notation is now equal to 11010
20 = 1
The highest coefficient less than 1 we can multiply this by to stay under 53 is 1
Multiplying this coefficient by our original value, we get: 1 * 1 = 1
Add our new value to our running total, we get:
52 + 1 = 53
This = 53, so we assign our outside coefficient of 1 for this digit.
Our new sum becomes 53
Our binary notation is now equal to 110101
