Find the largest of three consecutive even integers when six times the first integers is equal to fi

Find the largest of three consecutive even integers when six times the first integers is equal to five times the middle integer.

Let the first of the 3 consecutive even integers be n.
The second consecutive even integer is n + 2.
The third (largest) consecutive even integer is n + 4.

We are given 6n = 5(n + 2).

Multiply through on the right side, and we get:
6n = 5n + 10

Typing 6n = 5n + 10 into the search engine, we get n = 10.

Remember, n was our smallest of 3 consecutive even integers. So the largest is:
n + 4
10 + 4
14