Find the last digit of 2 raised to the 2020 no calculator

Check out this pattern:

2^1= 2
2^2= 4
2^3 = 8
2^4= 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256

The last digit repeats itself in blocks of 4
2, 4, 8, 6

We want to know what is the largest number in 1, 2, 3, 4 that divides 2020 without a remainder.

LEt's start with 4 and work backwards.
2020/4 = 505

Ever power of 2^4(n) ends in 6, so our answer is 6