The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, what are th

The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, what are the dimensions?

Set up 2 equations given P = 2l + 2w:

1. l = 2w - 6
2. 2l + 2w = 60

Substitute (1) into (2) for l:
2(2w - 6) + 2w = 60
4w - 12 + 2w = 60
6w - 12 = 60

To solve for w, type this into our math solver and we get:
w = 12

To solve for l, substitute w = 12 into (1)
l = 2(12) - 6
l = 24 - 6
l = 18