Find the last digit of 7^2013

Discussion in 'Calculator Requests' started by math_celebrity, Jan 24, 2024.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    Consider the first 8 calculations of 7 to an exponent:
    • 7^1 = 7
    • 7^2 = 49
    • 7^3 = 343
    • 7^4 = 2,401
    • 7^5 = 16,807
    • 7^6 = 117,649
    • 7^7 = 823,543
    • 7^8 = 5,764,801
    Take a look at the last digit of the first 8 calculations:
    7, 9, 3, 1, 7, 9, 3, 1

    The 7, 9, 3, 1 repeats through infinity.

    So every factor of 4, the cycle of 7, 9, 3, 1 restarts.

    Counting backwards from 2013, we know that 2012 is the largest number divisible by 4:
    7^2013 = 7^2012 * 7^1
    The cycle starts over after 2012.

    Which means the last digit of 7^2013 = 7

     
    Last edited: Jan 24, 2024

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