Find 2 consecutive integers with
a sum of 235
Setup relational equation
We need to find 2 integers, n and n + 1, who have a sum = 235
n + (n + 1) = 235
Grouping like terms, we get 2n + 1 = 235
Subtract 1 from each side:
2n + 1 - 1 = 235 - 1Cancel the ±1 from each side and simplify:
2n + 1 - 1 = 235 - 1
2n = 234
Divide each side by 2:
| 2n |
| = |
| 234 |
| 2 |
Cancel the 2's on the left side of the equation and simplify:
| = |
| 234 |
| 2 |
First Answer:
n = 117
Determine the 2nd Integer:
Now, since we found our first integer, our 2nd integer is just one greater:
(n + 1) = 117 + 1
Second Answer:
(n + 1) = 118
Final Answers:
n = 117
(n + 1) = 118
(n + 1) = 118
