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ƒ'()

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Given ƒ(x) = 3x4 + 6x3 - 123x2 - 126x + 1080
Determine the 2nd derivative ƒ''(x)

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Evaluate ƒ''(0)

ƒ''(0) = 12(0)3 + 18(0)2 - 246(0) - 126
ƒ''(0) = 12(0) + 18(0) - 246(0) - 126
ƒ''(0) = 0 + 0 + 0 - 126

Final Answer

ƒ''(0) = -126


You have 2 free calculationss remaining




What is the Answer?
ƒ''(0) = -126
How does the Functions-Derivatives-Integrals Calculator work?
Free Functions-Derivatives-Integrals Calculator - Given a polynomial expression, this calculator evaluates the following items:
1) Functions ƒ(x).  Your expression will also be evaluated at a point, i.e., ƒ(1)
2) 1st Derivative ƒ‘(x)  The derivative of your expression will also be evaluated at a point, i.e., ƒ‘(1)
3) 2nd Derivative ƒ‘‘(x)  The second derivative of your expression will be also evaluated at a point, i.e., ƒ‘‘(1)
4)  Integrals ∫ƒ(x)  The integral of your expression will also be evaluated on an interval, i.e., [0,1]
5) Using Simpsons Rule, the calculator will estimate the value of ≈ ∫ƒ(x) over an interval, i.e., [0,1]
This calculator has 7 inputs.

What 1 formula is used for the Functions-Derivatives-Integrals Calculator?

Power Rule: f(x) = xn, f‘(x) = nx(n - 1)

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What 8 concepts are covered in the Functions-Derivatives-Integrals Calculator?

derivative
rate at which the value y of the function changes with respect to the change of the variable x
exponent
The power to raise a number
function
relation between a set of inputs and permissible outputs
ƒ(x)
functions-derivatives-integrals
integral
a mathematical object that can be interpreted as an area or a generalization of area
point
an exact location in the space, and has no length, width, or thickness
polynomial
an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).
power
how many times to use the number in a multiplication
Example calculations for the Functions-Derivatives-Integrals Calculator

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