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ƒ()
ƒ'()

n =

Given ƒ(x) = 3x4 + 6x3 - 123x2 - 126x + 1080
Determine the 2nd derivative ƒ''(x)

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Start ƒ''(x)


Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 3, n = 4
and x is the variable we derive
ƒ''(x) = 3x4
ƒ''(x)( = 3 * 4)x(4 - 1)
ƒ''(x) = 12x3

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 6, n = 3
and x is the variable we derive
ƒ''(x) = 6x3
ƒ''(x)( = 6 * 3)x(3 - 1)
ƒ''(x) = 18x2

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -123, n = 2
and x is the variable we derive
ƒ''(x) = -123x2
ƒ''(x)( = -123 * 2)x(2 - 1)
ƒ''(x) = -246x

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = -126, n = 1
and x is the variable we derive
ƒ''(x) = -126x
ƒ''(x)( = -126 * 1)x(1 - 1)
ƒ''(x) = -126

Use the power rule

ƒ''(x) of axn = (a * n)x(n - 1)
For this term, a = 1080, n = 0
and x is the variable we derive
ƒ''(x) = 1080
ƒ''(x) = 0 <--- The derivative of a constant = 0. This is part of our answer.

Collecting all of our derivative terms

ƒ''(x) = 12x3 + 18x2 - 246x - 126

Evaluate ƒ''(0)

ƒ''(0) = 12(0)3 + 18(0)2 - 246(0) - 126
ƒ''(0) = 12(0) + 18(0) - 246(0) - 126
ƒ''(0) = 0 + 0 + 0 - 126

Final Answer


ƒ''(0) = -126