Evaluate the following logarithmic expression
1.02^y=1.77777777778
Take the natural log of both sides
Ln(1.02y) = Ln(1.77777777778)
Use a logarithmic identity
Ln(an) = n * Ln(a)
Using that identity, we have
n = y and a = 1.02, so our equation becomes:
yLn(1.02) = 0.57536414490481
0.01980262729618y = 0.57536414490481
Divide each side of the equation by 0.01980262729618
| 0.01980262729618y | |
| 0.01980262729618 |
| = |
| 0.57536414490481 |
| 0.01980262729618 |
Final Answer
y = 29.054939847088
