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Evaluate the combination:
4C3
A unique order or arrangement
nCr = | n! |
r!(n - r)! |
where n is the number of items
r is the unique arrangements.
4C3 2 | 4! |
3!(4 - 3)! |
n! = n * (n - 1) * (n - 2) * .... * 2 * 1
n! = 4!
4! = 4 x 3 x 2 x 1
4! = 24
(n - r)! = (4 - 3)!
(4 - 3)! = 1!
1! = 1
1! = 1
r! = 3!
3! = 3 x 2 x 1
3! = 6
4C3 = | 24 |
6 x 1 |
4C3 = | 24 |
6 |