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Evaluate the combination:
5C3
A unique order or arrangement
nCr = | n! |
r!(n - r)! |
where n is the number of items
r is the unique arrangements.
5C3 2 | 5! |
3!(5 - 3)! |
n! = n * (n - 1) * (n - 2) * .... * 2 * 1
n! = 5!
5! = 5 x 4 x 3 x 2 x 1
5! = 120
(n - r)! = (5 - 3)!
(5 - 3)! = 2!
2! = 2 x 1
2! = 2
r! = 3!
3! = 3 x 2 x 1
3! = 6
5C3 = | 120 |
6 x 2 |
5C3 = | 120 |
12 |