Evaluate the combination:
6C3
A unique order or arrangement
nCr = | n! |
r!(n - r)! |
where n is the number of items
r is the unique arrangements.
6C3 2 | 6! |
3!(6 - 3)! |
n! = n * (n - 1) * (n - 2) * .... * 2 * 1
n! = 6!
6! = 6 x 5 x 4 x 3 x 2 x 1
6! = 720
(n - r)! = (6 - 3)!
(6 - 3)! = 3!
3! = 3 x 2 x 1
3! = 6
r! = 3!
3! = 3 x 2 x 1
3! = 6
6C3 = | 720 |
6 x 6 |
6C3 = | 720 |
36 |