l sqrt(5)sqrt(7)
Enter square root or exponent statement:

Evaluate the following

57

Term 1 has a square root, so we evaluate and simplify:

We have a product of 2 square root terms

The product of square roots is equal to the square root of the products

57 = √5*7

57 = √35

Simplify √35.

Checking square roots, we see that

52 = 25 and 62 = 36

Our answer in decimal format is between 5 and 6

Our answer is not an integer

Simplify it into the product of an integer and a radical.

We do this by listing each product combo of 35

Check for integer square root values below:

35 = √135

35 = √57

From that list, the highest factor with an integer square root is 1

Therefore, we use the product combo √35 = √135

Evaluating square roots, we see that √1 = 1

Since 1 is the greatest common factor, this square root cannot be simplified any further:

Multiply by our constant of 1

Group square root terms for 1

1√35

Final Answer:



1√35