Enter 2 values below

<-- Length
<-- Width
<-- Area
<-- Perimeter
  

A rectangle has width of 4 and perimeter of 28

Calculate the length and area

Perimeter of a rectangle

P = 2(l x w)

Multiply the 2 through

P = 2l + 2w

Subtracting 2w from each side

P - 2w = 2l

Divide each side by 2

P - 2w
2
=
  
2l
2

l  =  P - 2w
  2

l  =  28 - 2(4)
  2

l  =  28 - 8
  2

l  =  20
  2

l = 10

Calculate Area (A):

A = l x w
where l = length and w = width

Plug in l = 10 and w = 4

A = 10 x 4

A = 40

Calculate diagonal length

Diagonal = √l2 + w2
where l = length and w = width

Plug in l = 10 and w = 4

Diagonal = √102 + 42

Diagonal = √100 + 16

Diagonal = √116

Diagonal = 10.770329614269

Calculate the circumradius R:

R  =  l2 + w2
  2

R  =  102 + 42
  2

R  =  100 + 16
  2

R  =  116
  2

R  =  10.770329614269
  2

R = 5.3851648071345

r  =  40
  14

Calculate the inradius r:

r  =  lw
  l + w

r  =  (10)(4)
  10 + 4

r  =  40
  14

r = 2.8571428571429

Other Properties:

Faces = 1

Edges = 4

Vertices = 4

Final Answers


w = 4
P = 28
A = 40
Diagonal = 10.770329614269
R = 5.3851648071345
r = 2.8571428571429
Faces = 1
Edges = 4
Vertices = 4