l
A rectangle has length x width of 10 x 5
Calculate the perimeter and area
A = l x w
where l = length and w = width
Plug in l = 10 and w = 5
A = 10 x 5
A = 50
P = 2(l + w)
where l = length and w = width
Plug in l = 10 and w = 5
P = 2 * (10 + 5)
P = 2 * 15
P = 30
Diagonal = √l2 + w2
where l = length and w = width
Plug in l = 10 and w = 5
Diagonal = √102 + 52
Diagonal = √100 + 25
Diagonal = √125
Diagonal = 11.180339887499
R = | √l2 + w2 |
2 |
R = | √102 + 52 |
2 |
R = | √100 + 25 |
2 |
R = | √125 |
2 |
R = | 11.180339887499 |
2 |
R = 5.5901699437495
r = | 50 |
15 |
r = | lw |
l + w |
r = | (10)(5) |
10 + 5 |
r = | 50 |
15 |
r = 3.3333333333333
Faces = 1
Edges = 4
Vertices = 4