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A rectangle has length x width of 20 x 9
Calculate the perimeter and area
A = l x w
where l = length and w = width
Plug in l = 20 and w = 9
A = 20 x 9
A = 180
P = 2(l + w)
where l = length and w = width
Plug in l = 20 and w = 9
P = 2 * (20 + 9)
P = 2 * 29
P = 58
Diagonal = √l2 + w2
where l = length and w = width
Plug in l = 20 and w = 9
Diagonal = √202 + 92
Diagonal = √400 + 81
Diagonal = √481
Diagonal = 21.931712199461
R = | √l2 + w2 |
2 |
R = | √202 + 92 |
2 |
R = | √400 + 81 |
2 |
R = | √481 |
2 |
R = | 21.931712199461 |
2 |
R = 10.965856099731
r = | lw |
l + w |
r = | (20)(9) |
20 + 9 |
r = | 180 |
29 |
r = 6.2068965517241
Faces = 1
Edges = 4
Vertices = 4