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A rectangle has length of 3 and perimeter of 50
Calculate the width and area
P = 2(l x w)
P = 2l + 2w
P - 2l = 2w
w = 22>
w = | P - 2l |
2 |
w = | 50 - 2(3) |
2 |
w = | 50 - 6 |
2 |
w = | 44 |
2 |
A = l x w
where l = length and w = width
Plug in l = 3 and w = 22
A = 3 x 22
A = 66
Diagonal = √l2 + w2
where l = length and w = width
Plug in l = 3 and w = 22
Diagonal = √32 + 222
Diagonal = √9 + 484
Diagonal = √493
Diagonal = 22.203603311175
R = | √l2 + w2 |
2 |
R = | √32 + 222 |
2 |
R = | √9 + 484 |
2 |
R = | √493 |
2 |
R = | 22.203603311175 |
2 |
R = 11.101801655587
r = | lw |
l + w |
r = | (3)(22) |
3 + 22 |
r = | 66 |
25 |
r = 2.64
Faces = 1
Edges = 4
Vertices = 4