Enter 2 values below

<-- Length
<-- Width
<-- Area
<-- Perimeter
  

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Answer

↓Steps Explained:↓

A rectangle has length of 505 and perimeter of 1520

Calculate the width and area

Perimeter of a rectangle

P = 2(l x w)

Multiply the 2 through

P = 2l + 2w

Subtracting 2l from each side

P - 2l = 2w

Divide each side by 2

w = 255>

w  =	P - 2l
	2

w  =	1520 - 2(505)
	2

w  =	1520 - 1010
	2

w  =	510
	2

Calculate Area (A):

A = l x w
where l = length and w = width

Plug in l = 505 and w = 255

A = 505 x 255

A = 128775

Calculate diagonal length

Diagonal = √l² + w²
where l = length and w = width

Plug in l = 505 and w = 255

Diagonal = √505² + 255²

Diagonal = √255025 + 65025

Diagonal = √320050

Diagonal = 565.72961739686

Calculate the circumradius R:

R  =	√l2 + w2
	2

R  =	√5052 + 2552
	2

R  =	√255025 + 65025
	2

R  =	√320050
	2

R  =	565.72961739686
	2

R = 282.86480869843

Calculate the inradius r:

r  =	lw
	l + w

r  =	(505)(255)
	505 + 255

r  =	128775
	760

r = 169.44078947368

Other Properties:

Faces = 1

Edges = 4

Vertices = 4

Final Answers

l = 505
P = 1520
w = 255
A = 128775
Diagonal = 565.72961739686
R = 282.86480869843
r = 169.44078947368
Faces = 1
Edges = 4
Vertices = 4

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