A rectangle has length x width of 8 x 5
Calculate the perimeter and area
A = l x w
where l = length and w = width
Plug in l = 8 and w = 5
A = 8 x 5
A = 40
P = 2(l + w)
where l = length and w = width
Plug in l = 8 and w = 5
P = 2 * (8 + 5)
P = 2 * 13
P = 26
Diagonal = √l2 + w2
where l = length and w = width
Plug in l = 8 and w = 5
Diagonal = √82 + 52
Diagonal = √64 + 25
Diagonal = √89
Diagonal = 9.4339811320566
R = | √l2 + w2 |
2 |
R = | √82 + 52 |
2 |
R = | √64 + 25 |
2 |
R = | √89 |
2 |
R = | 9.4339811320566 |
2 |
R = 4.7169905660283
r = | 40 |
13 |
r = | lw |
l + w |
r = | (8)(5) |
8 + 5 |
r = | 40 |
13 |
r = 3.0769230769231
Faces = 1
Edges = 4
Vertices = 4