Enter 2 values below

<-- Length
<-- Width
<-- Area
<-- Perimeter
  

A rectangle has length x width of 8 x 5

Calculate the perimeter and area

Calculate Area (A):

A = l x w
where l = length and w = width

Plug in l = 8 and w = 5

A = 8 x 5

A = 40

Calculate Perimeter (P):

P = 2(l + w)
where l = length and w = width

Plug in l = 8 and w = 5

P = 2 * (8 + 5)

P = 2 * 13

P = 26

Calculate diagonal length

Diagonal = √l2 + w2
where l = length and w = width

Plug in l = 8 and w = 5

Diagonal = √82 + 52

Diagonal = √64 + 25

Diagonal = √89

Diagonal = 9.4339811320566

Calculate the circumradius R:

R  =  l2 + w2
  2

R  =  82 + 52
  2

R  =  64 + 25
  2

R  =  89
  2

R  =  9.4339811320566
  2

R = 4.7169905660283

r  =  40
  13

Calculate the inradius r:

r  =  lw
  l + w

r  =  (8)(5)
  8 + 5

r  =  40
  13

r = 3.0769230769231

Other Properties:

Faces = 1

Edges = 4

Vertices = 4

Final Answers


l = 8
w = 5
A = 40
P = 26
Diagonal = 9.4339811320566
R = 4.7169905660283
r = 3.0769230769231
Faces = 1
Edges = 4
Vertices = 4