Use Substitution to solve 10v 6b = 276 and 5v 2b = 117
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Use the substitution method to solve:
10v + 6b = 276
5v + 2b = 117
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for v:
5v + 2b = 117
Subtract 2b from both sides to isolate v:
5v + 2b - 2b = 117 - 2b
5v = 117 - 2b
Now divide by 5:
5v
5
=
117 - 2b
5
Revised Equation 2:
v =
117 - 2b
5
Plug Revised Equation 2 value into v:
10(v) + 6b = 276
10 * ((117 - 2b)/5) + 6b = 276
((1170 - 20b)/5) + 6b = 276
Multiply equation 1 through by 5
5 * (((1170 - 20b)/5) + 6b = 276)
5 * (((1170 - 20b)/5) + 6b = 276)
1170 - 20b + 30b = 1380
Group like terms:
-20b + 30b = 1380 - 1170
10b = 210
Divide each side by 10
10b
10
=
210
10
b =
210
10
b = 21
Plug this answer into Equation 1
10v + 6(21) = 276
10v + 126 = 276
10v = 276 - 126
10v = 150
Divide each side by 10
10v
10
=
150
10
v =
150
10
v = 15
What is the Answer?
v = 15 and b = 21
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Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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