Use the substitution method to solve:
12c + 8t = 34
10c + 7t = 29
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
10c + 7t = 29
Subtract 7t from both sides to isolate c:
10c + 7t - 7t = 29 - 7t
10c = 29 - 7t
Now divide by 10:
| 10c | |
| 10 |
| = |
| 29 - 7t |
| 10 |
Revised Equation 2:
| c = | 29 - 7t |
| 10 |
Plug Revised Equation 2 value into c:
12(c) + 8t = 34
12 * ((29 - 7t)/10) + 8t = 34
((348 - 84t)/10) + 8t = 34
Multiply equation 1 through by 10
10 * (((348 - 84t)/10) + 8t = 34)
10 * (((348 - 84t)/10) + 8t = 34)
348 - 84t + 80t = 340
Group like terms:
-84t + 80t = 340 - 348
-4t = -8
Divide each side by -4
| -4t | |
| -4 |
| = |
| -8 |
| -4 |
| t = | -8 |
| -4 |
t = 2
Plug this answer into Equation 1
12c + 8(2) = 34
12c + 16 = 34
12c = 34 - 16
12c = 18
Divide each side by 12
| 12c | |
| 12 |
| = |
| 18 |
| 12 |
| c = | 18 |
| 12 |
c = 1.5
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