Use Substitution to solve 5c 3t = 37 and 2c 6t = 64

Crop Image

Use the substitution method to solve:

5c + 3t = 37

2c + 6t = 64

Check Format

Equation 1 is in the correct format.

Check Format

Equation 2 is in the correct format.

Rearrange Equation 2 to solve for c:

2c + 6t = 64

Subtract 6t from both sides to isolate c:

2c + 6t - 6t = 64 - 6t

2c = 64 - 6t

Now divide by 2:

2c

2

=

64 - 6t

2

Revised Equation 2:

c =

64 - 6t

2

Plug Revised Equation 2 value into c:

5(c) + 3t = 37

5 * ((64 - 6t)/2) + 3t = 37

((320 - 30t)/2) + 3t = 37

Multiply equation 1 through by 2

2 * (((320 - 30t)/2) + 3t = 37)

2 * (((320 - 30t)/2) + 3t = 37)

320 - 30t + 6t = 74

Group like terms:

-30t + 6t = 74 - 320

-24t = -246

Divide each side by -24

-24t

-24

=

-246

-24

t =

-246

-24

t = 10.25

Plug this answer into Equation 1

5c + 3(10.25) = 37

5c + 30.75 = 37

5c = 37 - 30.75

5c = 6.25

Divide each side by 5

5c

5

=

6.25

5

c =

6.25

5

c = 1.25

What is the Answer?

c = 1.25 and t = 10.25

How does the Simultaneous Equations Calculator work?

Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
Pick any 3 of the methods to solve the systems of equations
2 equations 2 unknowns This calculator has 2 inputs.

What 1 formula is used for the Simultaneous Equations Calculator?