Use Substitution to solve 5c + 3t = 37 and 2c + 6t = 64
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Use the substitution method to solve:
5c + 3t = 37
2c + 6t = 64
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
2c + 6t = 64
Subtract 6t from both sides to isolate c:
2c + 6t - 6t = 64 - 6t
2c = 64 - 6t
Now divide by 2:
2c
2
=
64 - 6t
2
Revised Equation 2:
c =
64 - 6t
2
Plug Revised Equation 2 value into c:
5(c) + 3t = 37
5 * ((64 - 6t)/2) + 3t = 37
((320 - 30t)/2) + 3t = 37
Multiply equation 1 through by 2
2 * (((320 - 30t)/2) + 3t = 37)
2 * (((320 - 30t)/2) + 3t = 37)
320 - 30t + 6t = 74
Group like terms:
-30t + 6t = 74 - 320
-24t = -246
Divide each side by -24
-24t
-24
=
-246
-24
t =
-246
-24
t = 10.25
Plug this answer into Equation 1
5c + 3(10.25) = 37
5c + 30.75 = 37
5c = 37 - 30.75
5c = 6.25
Divide each side by 5
5c
5
=
6.25
5
c =
6.25
5
c = 1.25
What is the Answer?
c = 1.25 and t = 10.25
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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