Use Substitution to solve c + v = 40 and 4c + 6v = 180
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Use the substitution method to solve:
c + v = 40
4c + 6v = 180
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
4c + 6v = 180
Subtract 6v from both sides to isolate c:
4c + 6v - 6v = 180 - 6v
4c = 180 - 6v
Now divide by 4:
4c
4
=
180 - 6v
4
Revised Equation 2:
c =
180 - 6v
4
Plug Revised Equation 2 value into c:
1(c) + v = 40
1 * ((180 - 6v)/4) + v = 40
((180 - 6v)/4) + v = 40
Multiply equation 1 through by 4
4 * (((180 - 6v)/4) + v = 40)
4 * (((180 - 6v)/4) + v = 40)
180 - 6v + 4v = 160
Group like terms:
-6v + 4v = 160 - 180
-2v = -20
Divide each side by -2
-2v
-2
=
-20
-2
v =
-20
-2
v = 10
Plug this answer into Equation 1
1c + 1(10) = 40
1c + 10 = 40
1c = 40 - 10
1c = 30
Divide each side by 1
1c
1
=
30
1
c =
30
1
c = 30
What is the Answer?
c = 30 and v = 10
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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