Use the substitution method to solve:
l + t = 12
3l + 2t = 32
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for l:
3l + 2t = 32
Subtract 2t from both sides to isolate l:
3l + 2t - 2t = 32 - 2t
3l = 32 - 2t
Now divide by 3:
| 3l | |
| 3 |
| = |
| 32 - 2t |
| 3 |
Revised Equation 2:
| l = | 32 - 2t |
| 3 |
Plug Revised Equation 2 value into l:
1(l) + t = 12
1 * ((32 - 2t)/3) + t = 12
((32 - 2t)/3) + t = 12
Multiply equation 1 through by 3
3 * (((32 - 2t)/3) + t = 12)
3 * (((32 - 2t)/3) + t = 12)
32 - 2t + 3t = 36
Group like terms:
-2t + 3t = 36 - 32
1t = 4
Divide each side by 1
| 1t | |
| 1 |
| = |
| 4 |
| 1 |
| t = | 4 |
| 1 |
t = 4
Plug this answer into Equation 1
1l + 1(4) = 12
1l + 4 = 12
1l = 12 - 4
1l = 8
Divide each side by 1
| 1l | |
| 1 |
| = |
| 8 |
| 1 |
| l = | 8 |
| 1 |
l = 8
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