Use Substitution to solve m + t = 20 and 11m + 3t = 100
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Use the substitution method to solve:
m + t = 20
11m + 3t = 100
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for m:
11m + 3t = 100
Subtract 3t from both sides to isolate m:
11m + 3t - 3t = 100 - 3t
11m = 100 - 3t
Now divide by 11:
11m
11
=
100 - 3t
11
Revised Equation 2:
m =
100 - 3t
11
Plug Revised Equation 2 value into m:
1(m) + t = 20
1 * ((100 - 3t)/11) + t = 20
((100 - 3t)/11) + t = 20
Multiply equation 1 through by 11
11 * (((100 - 3t)/11) + t = 20)
11 * (((100 - 3t)/11) + t = 20)
100 - 3t + 11t = 220
Group like terms:
-3t + 11t = 220 - 100
8t = 120
Divide each side by 8
8t
8
=
120
8
t =
120
8
t = 15
Plug this answer into Equation 1
1m + 1(15) = 20
1m + 15 = 20
1m = 20 - 15
1m = 5
Divide each side by 1
1m
1
=
5
1
m =
5
1
m = 5
What is the Answer?
m = 5 and t = 15
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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