Enter 2 points 1 point and the slope

Point 1:
(x1 = , y1 = )   Slope:
Point 2:
(x2 = , y2 = )    b:

Given (1, 5) and (2, 14)

calculate 8 items:

Calculate the slope and point-slope form:

Slope (m)  =  y2 - y1
  x2 - x1

Slope (m)  =  14 - 5
  2 - 1

Slope (m)  =  9
  1

Slope = 9

Calculate the point-slope form :

y - y1 = m(x - x1)

y - 5 = 9(x - 1)

Calculate the line equation

Standard equation of a line is y = mx + b
where m is our slope
x and y are points on the line
b is a constant.

Rearrange the equation to solve for b
we get b = y - mx.
Use (1, 5) and the slope (m) = 9

b = 5 - (9 * 1)

b = 5 + 9

b  =  -4
  1

Solve for b

b = -4

Build standard line equation

y = 9x - 4

Distance between the 2 points

D = Square Root((x2 - x1)2 + (y2 - y1)2)

D = Square Root((2 - 1)2 + (14 - 5)2)

D = Square Root((12 + 92))

D = √(1 + 81)

D = √82

D = 9.0554

Midpoint between the 2 points

Midpoint =
  
x2 + x1
2
  
,
y2 + y1
2
Midpoint =
  
1 + 2
2
  
,
5 + 14
2

Midpoint =
  
3
2
  
,
19
2

Form a right triangle

Plot a 3rd point (2,5)

Our first triangle side = 2 - 1 = 1

Our second triangle side = 14 - 5 = 9

Using the slope we calculated
Tan(Angle1) = 9

Angle1 = Atan(9)

Angle1 = 83.6598°

Since we have a right triangle
We only have 90° left
Angle2 = 90 - 83.6598° = 6.3402

Calculate the y intercept of our line

The y intercept is found by
Setting x = 0 in y = 9x - 4

y = 9(0) - 4

y = -4

Find the parametric equations for the line

Parametric equations are written as
(x,y) = (x0,y0) + t(b,-a)

Plugging in our numbers, we get

(x,y) = (1,5) + t(2 - 1,14 - 5)

(x,y) = (1,5) + t(1,9)

x = 1 + t

y = 5 + 9t

Calculate Symmetric Equations:

x - x0
z
  
y - y0
b

Plugging in our numbers, we get:

x - 1
1
  
y - 5
9

Plot both points and line on the Cartesian Graph:

Final Answers


Slope = 9/1 or 9
Slope Intercept = y = 9x - 4
Distance Between Points = 9.0554
Midpoint = (3/2, 19/2)
Angle 1 = 83.6598
Angle 2 = 6.3402
Y-intercept = -4