The sum of 3 consecutive numbers equals 273
What are the 3 numbers?
Setup Relational Equation
1) Set up an equation where our numbers are n, n + 1, n + 2
2) We increment by 1 for each number since we have numbers.
3) We set this sum of consecutive numbers equal to 273
n + (n + 1) + (n + 2) = 273
Simplify this equation by grouping variables and constants together:
(n + n + n) + 1 + 2 = 273
3n + 3 = 273
Subtract 3 from each side to isolate 3n:
3n + 3 - 3 = 273 - 3
Cancel the 3 on the left side and we get:
3n + 3 - 3 = 273 - 3
3n = 270
Divide each side of the equation by 3 to isolate n:
| 3n | |
| 3 |
| = |
| 270 |
| 3 |
Cancel the 3 on the left side:
| = |
| 270 |
| 3 |
n = 90
Call this n1, so we find our other 2 numbers
n2 = n1 + 1
n2 = 90 + 1
n2 = 91
n3 = n2 + 1
n3 = 91 + 1
n3 = 92
List out the 3 consecutive numbers
90 ← 1st number, or the Smallest, Minimum, Least Value
91 ← 2nd number
92 ← 3rd or the Largest, Maximum, Highest Value
Check your work:
90 + 91 + 92 ? 273
273 = 273
Final Answer:
(90, 91, 92)
