The sum of 3 consecutive numbers equals 240

What are the 3 numbers?

1) Set up an equation where our numbers are n, n + 1, n + 2

2) We increment by 1 for each number since we have *numbers*.

3) We set this sum of consecutive *numbers* equal to 240

n + (n + 1) + (n + 2) = 240

(n + n + n) + 1 + 2 = 240

3n + 3 = 240

3n + 3 - 3 = 240 - 3

~~3~~n + ~~3~~ - ~~3~~ = 240 - 3

3n = 237

3n | |

3 |

= |

237 |

3 |

= |

237 |

3 |

n = **79**

Call this n_{1}, so we find our other 2 numbers

n_{2} = n_{1} + 1

n_{2} = 79 + 1

n_{2} = **80**

n_{3} = n_{2} + 1

n_{3} = 80 + 1

n_{3} = **81**

79 ← 1*st* number, or the Smallest, Minimum, Least Value

80 ← 2*nd* number

81 ← 3*rd* or the Largest, Maximum, Highest Value

79 + 80 + 81 ? 240

240 = 240

(**79, 80, 81**)

(**79, 80, 81**)

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This calculator has 1 input.

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sum of three consecutive odd integers

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sum of four consecutive odd numbers

sum of four consecutive even numbers

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sum of 5 consecutive numbers

sum of 5 consecutive even integers

sum of 5 consecutive odd integers

sum of 5 consecutive even numbers

sum of 5 consecutive odd numbers

sum of five consecutive integers

sum of five consecutive odd integers

sum of five consecutive even integers

sum of five consecutive numbers

sum of five consecutive odd numbers

sum of five consecutive even numbers

This calculator has 1 input.

Given an integer n, the next consecutive number is n + 1

For more math formulas, check out our Formula Dossier

For more math formulas, check out our Formula Dossier

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