The sum of 3 consecutive numbers equals 12

What are the 3 numbers?

1) Set up an equation where our numbers are n, n + 1, n + 2

2) We increment by 1 for each number since we have *numbers*.

3) We set this sum of consecutive *numbers* equal to 12

n + (n + 1) + (n + 2) = 12

(n + n + n) + 1 + 2 = 12

3n + 3 = 12

3n + 3 - 3 = 12 - 3

~~3~~n + ~~3~~ - ~~3~~ = 12 - 3

3n = 9

3n | |

3 |

= |

9 |

3 |

= |

9 |

3 |

n = **3**

Call this n_{1}, so we find our other 2 numbers

n_{2} = n_{1} + 1

n_{2} = 3 + 1

n_{2} = **4**

n_{3} = n_{2} + 1

n_{3} = 4 + 1

n_{3} = **5**

3 ← 1*st* number, or the Smallest, Minimum, Least Value

4 ← 2*nd* number

5 ← 3*rd* or the Largest, Maximum, Highest Value

3 + 4 + 5 ? 12

12 = 12

(**3, 4, 5**)

(**3, 4, 5**)

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This calculator has 1 input.

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sum of 5 consecutive even numbers

sum of 5 consecutive odd numbers

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sum of five consecutive odd integers

sum of five consecutive even integers

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sum of five consecutive odd numbers

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This calculator has 1 input.

Given an integer n, the next consecutive number is n + 1

For more math formulas, check out our Formula Dossier

For more math formulas, check out our Formula Dossier

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