−i × 2i × 3i

Discussion in 'Calculator Requests' started by math_celebrity, Feb 2, 2024.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    (-1 x 2 x 3)(i x i x i) = 6i^3
    -6i^3 = -6 x i^2 x I

    We know that i = sqrt(-1)
    i^2 = sqrt(-1) x sqrt(-1)
    i^2 = -1
    -6(-1)(i)
    6i

     
    Last edited: Feb 3, 2024

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