A cable company charges $75 for installation plus $20 per month. Another cable company offers free i

Discussion in 'Calculator Requests' started by math_celebrity, Nov 21, 2020.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    A cable company charges $75 for installation plus $20 per month. Another cable company offers free installation but charges $35 per month. For how many months of cable service would the total cost from either company be the same

    Set ups the cost function for the first cable company C(m) where m is the number of months:
    C(m) = cost per month * m + installation fee
    C(m) = 20m + 75

    Set ups the cost function for the second cable company C(m) where m is the number of months:
    C(m) = cost per month * m + installation fee
    C(m) = 35m

    The problem asks for m when both C(m) functions are equal. So we set both C(m) functions equal and solve for m:
    20m + 75 = 35m

    To solve for m, we type this equation into our search engine and we get:
    m = 5
     

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