A car is purchased for $24,000 . Each year it loses 30% of its value. After how many years will t

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  1. math_celebrity

    math_celebrity Administrator Staff Member

    A car is purchased for $24,000 . Each year it loses 30% of its value. After how many years will the car be worth $7300 or less? (Use the calculator provided if necessary.) Write the smallest possible whole number answer.

    Set up the depreciation equation D(t) where t is the number of years in the life of the car:
    D(t) = 24,000 * (1 - 0.3)^t
    D(t) = 24000 * (0.7)^t

    The problem asks for D(t)<=7300
    24000 * (0.7)^t = 7300

    Divide each side by 24000
    (0.7)^t = 7300/24000
    (0.7)^t= 0.30416666666

    Take the natural log of both sides:
    LN(0.7^t) = -1.190179482215518

    Using the natural log identities, we have:
    t * LN(0.7) = -1.190179482215518
    t * -0.35667494393873245= -1.190179482215518

    Divide each side by -0.35667494393873245
    t = 3.33687437943
    Rounding this up, we have t = 4
     
    Last edited: Jan 14, 2024

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