A man is 5 years older than his wife, and the daughter age is half of the mother, and if you add the

Discussion in 'Calculator Requests' started by math_celebrity, Mar 30, 2020.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    A man is 5 years older than his wife, and the daughter age is half of the mother, and if you add their ages is equal 100

    Let the man's age be m. Let the wife's age be w. Let the daughter's age be d. We're given:
    1. m = w + 5
    2. d = 0.5m
    3. d + m + w = 100
    Rearrange equation 1 in terms of w my subtracting 5 from each side:
    1. w = m - 5
    2. d = 0.5m
    3. d + m + w = 100
    Substitute equation (1) and equation (2) into equation (3)
    0.5m + m + m - 5 = 100

    We type this equation into our search engine to solve for m and we get:
    m = 42

    Now, substitute m = 42 into equation 2 to solve for d:
    d = 0.5(42)
    d = 21

    Now substitute m = 42 into equation 1 to solve for w:
    w = 42 - 5
    w = 37

    To summarize our ages:
    • Man (m) = 42 years old
    • Daughter (d) = 21 years old
    • Wife (w) = 37 years old
     

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