Company a charges $25 plus $0.10 a mile. Company b charges $20 plus $0.15 per mile. How far would yo

Discussion in 'Calculator Requests' started by math_celebrity, Sep 13, 2016.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    Company a charges $25 plus $0.10 a mile. Company b charges $20 plus $0.15 per mile. How far would you need to travel to get each charge to be the same?

    Let x be the number of miles traveled
    Company A charge: C = 25 + 0.10x
    Company B charge: C = 20 + 0.15x

    Set up an equation find out when the charges are the same.
    25 + 0.10x = 20 + 0.15x

    Combine terms and simplify
    0.05x = 5

    Divide each side of the equation by 0.05 to isolate x
    x = 100
     

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