cscx-cotx*cosx=sinx

Discussion in 'Calculator Requests' started by math_celebrity, Aug 11, 2021.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    cscx-cotx*cosx=sinx

    A few transformations we can make based on trig identities:
    • csc(x) = 1/sin(x)
    • cot(x) = cos(x)/sin(x)
    So we have:
    1/sin(x) - cos(x)/sin(x) * cos(x) = sin(x)
    (1 - cos^2(x))/sin(x) = sin(x)

    1 - cos^2(x) = sin^2(x)

    This is true from the identity:
    sin^2(x) - cos^2(x) = 1
     

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