Find 3 Even Integers with a sum of 198 Let x be the first even integer. Then y is the next, and z is the third even integer. y = x + 2 z = x + 4 x + y + z = 198 Substituting y and z into (3): x + x + 2 + x + 4 = 198 Group x terms 3x + 6 = 198 Using our equation solver, we get: x = 64 y = 64 + 2 y= 66 z = 64 + 4 z = 68