If f(x) = 3x + 1 and g(x) = x^2 + 2x, find x when f(g(x)) = 10 Evaluate f(g(x)) f(g(x)) = 3(x^2 + 2x) + 1 f(g(x)) = 3x^2 + 6x + 1 When f(g(x)) = 10, we have 10 = 3x^2 + 6x + 1 Subtract 10 from each side: 3x^2 + 6x - 9 = 0 Divide each side of the equation by 3 x^2 + 2x - 3 = 0 Factor, we have: (x + 3)(x - 1) = 0 So x is either 1 or -3