math_celebrity Administrator Staff member Jun 14, 2019 #1 In 2010, the population of Greenbow, AL was 1,100 people. The population has risen at at rate of 4% each year since. Let x = the number of years since 2010 and y = the population of Greenbow. What will the population of Greenbow be in 2022? P(x) = 1,100(1.04)^x x = 2022 - 2010 x = 12 years We want P(12): P(12) = 1,100(1.04)^12 P(12) = 1,100(1.60103221857) P(12) = 1,761.14 ~ 1,761

In 2010, the population of Greenbow, AL was 1,100 people. The population has risen at at rate of 4% each year since. Let x = the number of years since 2010 and y = the population of Greenbow. What will the population of Greenbow be in 2022? P(x) = 1,100(1.04)^x x = 2022 - 2010 x = 12 years We want P(12): P(12) = 1,100(1.04)^12 P(12) = 1,100(1.60103221857) P(12) = 1,761.14 ~ 1,761