Show all factor pairs, prime factorization,
sum of factors (divisors), aliquot sum,
and prime power decomposition of 12
1) 0 < Factor Pairs ≤ 12
2) The factor pair product = 12
Number | Factor Pairs | Factor Pairs Sum |
---|---|---|
12 | 1 x 12 | 13 |
12 | 2 x 6 | 8 |
12 | 3 x 4 | 7 |
There are 3 factor pairs of 12
1, 2, 3, 4, 6, 12
τ(12) = 6
1, 3
2, 4, 6, 12
Proper factors are all factors except for the number itself
in this case 12
1, 2, 3, 4, 6
12 = 2 x 6 <--- 2 is a prime number
Reduce 6 to the product of primes:
6 = 3 x 2 <--- 3 is a prime number
Reduce 2 to the product of primes:
2 x 2 x 3
22 x 3
1 + 12 + 2 + 6 + 3 + 4 = 28
This is the sum of all the factors except the number
1 + 2 + 6 + 3 + 4 = 16