Show all factor pairs, prime factorization,
sum of factors (divisors), aliquot sum,
and prime power decomposition of 36
1) 0 < Factor Pairs ≤ 36
2) The factor pair product = 36
Number | Factor Pairs | Factor Pairs Sum |
---|---|---|
36 | 1 x 36 | 37 |
36 | 2 x 18 | 20 |
36 | 3 x 12 | 15 |
36 | 4 x 9 | 13 |
36 | 6 x 6 | 12 |
There are 5 factor pairs of 36
1, 2, 3, 4, 6, 9, 12, 18, 36
τ(36) = 9
1, 3, 9
2, 4, 6, 12, 18, 36
Proper factors are all factors except for the number itself
in this case 36
1, 2, 3, 4, 6, 9, 12, 18
36 = 2 x 18 <--- 2 is a prime number
Reduce 18 to the product of primes:
18 = 3 x 6 <--- 3 is a prime number
Reduce 6 to the product of primes:
6 = 2 x 3 <--- 2 is a prime number
Reduce 3 to the product of primes:
2 x 2 x 3 x 3
22 x 32
1 + 36 + 2 + 18 + 3 + 12 + 4 + 9 + 6 = 91
This is the sum of all the factors except the number
1 + 2 + 18 + 3 + 12 + 4 + 9 + 6 = 55