Enter polynomial 1

Enter polynomial 2

  

Using polynomial long division, evaluate the expression below:
x2 - 6x + 8
x - 3

First, we write our expression in long division format and follow the steps below.

Step 1
 1a)  Divide the first term of the dividend by the first term of the divisor → x2 ÷ x = 1x(2 - 1) = x
 1b)  We multiply that part of the quotient by the divisor → x(x - 3) = x2 - 3x  →  Click here to see the Math for this Multiplication.
 1c)  Subtract x2 - 3x from x2 - 6x + 8 to get -3x + 8  →  Click here to see the Math.

      x
x - 3x2 - 6x + 8
   x2 - 3x     
     -3x + 8   


Step 2
 2a)  Divide the first term of the dividend by the first term of the divisor → -3x ÷ x = -3x(1 - 1) = -3
 2b)  We multiply that part of the quotient by the divisor → -3(x - 3) = -3x + 9  →  Click here to see the Math for this Multiplication.
 2c)  Subtract -3x + 9 from -3x + 8 to get -1  →  Click here to see the Math.

      x - 3
x - 3x2 - 6x + 8
   x2 - 3x     
     -3x + 8   
     -3x + 9   
       -1   


We have a remainder leftover. We take our answer piece and remainder piece below
Answer = x - 3
Remainder piece = Leftover answer divided by our denominator
-1
x - 3