| x2 - 6x + 8 |
| x - 3 |
First, we write our expression in long division format and follow the steps below.
Step 1
1a) Divide the first term of the dividend by the first term of the divisor → x2 ÷ x = 1x(2 - 1) = x
1b) We multiply that part of the quotient by the divisor → x(x - 3) = x2 - 3x → Click here to see the Math for this Multiplication.
1c) Subtract x2 - 3x from x2 - 6x + 8 to get -3x + 8 → Click here to see the Math.
| x | |||||||
| x | - | 3 | x2 | - | 6x | + | 8 | x2 | - | 3x | -3x | + | 8 |
Step 2
2a) Divide the first term of the dividend by the first term of the divisor → -3x ÷ x = -3x(1 - 1) = -3
2b) We multiply that part of the quotient by the divisor → -3(x - 3) = -3x + 9 → Click here to see the Math for this Multiplication.
2c) Subtract -3x + 9 from -3x + 8 to get -1 → Click here to see the Math.
| x | - | 3 | |||||
| x | - | 3 | x2 | - | 6x | + | 8 | x2 | - | 3x | -3x | + | 8 | -3x | + | 9 | -1 |
We have a remainder leftover. We take our answer piece and remainder piece below
Answer = x - 3
Remainder piece = Leftover answer divided by our denominator
| -1 |
| x - 3 |
