Enter 2 numbers for Basic Math Operations:
Use long division with remainders:
54 ÷ 15:
| 0 | ||||||
| 1 | 5 | 5 | 4 | |||
| 0 | <---- 0 x 15 = 0 | |||||
| 5 | <---- 5 - 0 = 5 |
| 0 | 3 | ||||||
| 1 | 5 | 5 | 4 | ||||
| 0 | |||||||
| 5 | 4 | <---- Bring down the 4 from the numerator | |||||
| 4 | 5 | <---- 3 x 15 = 45 | |||||
| 9 | <---- 54 - 45 = 9 |
We still have 9 leftover, and no more numbers to bring down, so we have our remainder term:
| 0 | 3 | R 9 |
| 1 | 5 |
| 5 | 4 |
Expressing our remainder as a fraction: Remainder/Denominator, we get:
| Remainder = | 9 |
| 15 |
Our fraction portion is not reduced down completely. Using our GCF calculator, we see the Greatest Common Factor (GCF) of 9 and 15 is 3.
Dividing the numerator and denominator by the GCF, we get:
| Numerator = | 9 |
| 3 |
Numerator: = 3
| Denominator = | 15 |
| 3 |
Denominator: = 5
Answer in Fractional Remainder Form = 3 & 3/5
54 ÷ 15 = 3 r 9 or 3 & 3/5
Final Answer
Answer = 54 ÷ 15 = 3 r 9 or 3 & 3/5
